Solving the Classic FizzBuzz Problem in Python: A Step-by-Step Tutorial

If you’re learning to code, you’ll almost certainly encounter the FizzBuzz problem. It’s a classic programming challenge often used in interviews to test basic logic and control flow. The rules are simple, but it’s a great exercise for practicing loops and conditional statements.

📜 The Rules of FizzBuzz

The goal is to loop through numbers from 1 to 100 and for each number, print one of the following:

  • “Fizz” if the number is divisible by 3.
  • “Buzz” if the number is divisible by 5.
  • “FizzBuzz” if the number is divisible by both 3 and 5.
  • The number itself, if none of the above conditions are true.

➗ Using the Modulo Operator

The key to solving FizzBuzz is the modulo operator (%). This operator gives you the remainder of a division. If `number % 3` is equal to 0, it means the number is perfectly divisible by 3. We can use this inside `if` statements to check our conditions.

💻 A Step-by-Step Solution

First, we need a loop to go through numbers 1 to 100. A for loop with `range(1, 101)` is perfect for this. Inside the loop, we use an `if-elif-else` chain to check the conditions in the correct order. It’s important to check for divisibility by *both* 3 and 5 first, because if we checked for just 3 first, we would print “Fizz” for a number like 15 and never get to the “FizzBuzz” check.
for num in range(1, 101):
    if num % 3 == 0 and num % 5 == 0:
        print("FizzBuzz")
    elif num % 3 == 0:
        print("Fizz")
    elif num % 5 == 0:
        print("Buzz")
    else:
        print(num)

And that’s it! While simple, FizzBuzz is a fantastic way to solidify your understanding of fundamental programming concepts.

Stephenson, Ben. The Python Workbook: A Brief Introduction with Exercises and Solutions. 3rd ed., Springer, 2025.

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